divisor_of_p-1_factorization_method.sf 1.7 KB

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  1. #!/usr/bin/ruby
  2. # Author: Daniel "Trizen" Șuteu
  3. # Date: 27 February 2022
  4. # https://github.com/trizen
  5. # A new special-purpose integer factorization method, finding a factor of n
  6. # if a large enough divisor of p-1 is known, where p is a prime dividing n.
  7. func dpm1_factor(n, pm1_divisor = 1, reps = 1e3) {
  8. for k in (1..reps) {
  9. var a = pm1_divisor*k
  10. var u = idiv(n, a)
  11. break if (u <= 1)
  12. bsearch_le(2, u, {|b|
  13. #var x = idiv(isqrt(a*a + 4*a*b*n - 2*a*b + b*b) - a - b, 2*a*b)
  14. var (x) = iquadratic_formula(a*b, a+b, 1-n)
  15. var t = ((x*a + 1) * (x*b + 1))
  16. var g = gcd(t, n)
  17. if (g.is_between(2, n-1)) {
  18. say "[#{k} tries] Found factor: #{g} with a,b = [#{a}, #{b}] and x = #{x}"
  19. return g
  20. }
  21. break if (n/t < 1.001) # optimization
  22. n <=> t
  23. })
  24. }
  25. return 1
  26. }
  27. dpm1_factor(503*863, 2) #=> 503
  28. dpm1_factor(2**64 + 1, 256) #=> 274177
  29. dpm1_factor(2**128 + 1, 116503103764643) #=> 59649589127497217
  30. dpm1_factor((114*(2**127 - 1) + 1) * random_prime(1e50), 2**127 - 1) #=> 19396094914493492417412352623610788052879
  31. __END__
  32. [36 tries] Found factor: 503 with a,b = [72, 1508] and x = 1
  33. [17 tries] Found factor: 274177 with a,b = [4352, 1034834473201] and x = 63
  34. [256 tries] Found factor: 59649589127497217 with a,b = [29824794563748608, 1426172300171282287590] and x = 2
  35. [38 tries] Found factor: 19396094914493492417412352623610788052879 with a,b = [6465364971497830805804117541203596017626, 4102844459326514132014637137633862970170675382519] and x = 3