745 Sum of Squares -- v2.sf 1005 B

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  1. #!/usr/bin/ruby
  2. # Daniel "Trizen" Șuteu
  3. # Date: 31 January 2021
  4. # https://github.com/trizen
  5. # Sum of Squares
  6. # https://projecteuler.net/problem=745
  7. # Formula:
  8. # S(n) = Sum_{k=1..floor(sqrt(n))} k^2 * R(floor(n/k^2))
  9. # Where R(n) is the number of squarefree numbers <= n:
  10. # R(n) = Sum_{k=1..floor(sqrt(n))} moebius(k) * floor(n/k^2)
  11. # Faster formula:
  12. # S(n) = Sum_{k=1..floor(sqrt(n))} J_2(k) * floor(n / k^2)
  13. # where J_n(x) is the Jordan totient function.
  14. # S(10^1) = 24
  15. # S(10^2) = 767
  16. # S(10^3) = 22606
  17. # S(10^4) = 722592
  18. # S(10^5) = 22910120
  19. # S(10^6) = 725086120
  20. # S(10^7) = 22910324448
  21. # S(10^8) = 724475280152
  22. # S(10^9) = 22907428923832
  23. # S(10^10) = 724420596049320
  24. # S(10^11) = 22908061437420776
  25. # S(10^12) = 724418227020757048
  26. # S(10^13) = 22908104289912800016
  27. # Runtime: 1 minute, 53 seconds (previously: ~3 minutes).
  28. define MOD = 1_000_000_007
  29. func S(n) {
  30. sum(1..n.isqrt, {|k|
  31. mulmod(idiv(n, k.sqr), k.jordan_totient(2), MOD)
  32. })
  33. }
  34. say (S(10**14) % MOD)